Proof of cancellation of nodes

Proposition (Completeness for shuffles). If [[s1]]  [[s2]] then s1 = s2.

Proposition (Cancellation of nodes). For any:

we can find h such that:
=

Proof. First, show a result about bisimulation on graphs; if:

then either:

or we can find h such that:

We now proceed by induction on f, which (by normalization) we can assume is in normal form. We have three cases:

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